lar::util::details::has_dereference_class< T, Enable > Struct Template Reference

Class defining whether the specified type can be dereferenced. More...

#include <Dereference.h>

Inheritance diagram for lar::util::details::has_dereference_class< T, Enable >:

Detailed Description

template<typename T, typename Enable = void>
struct lar::util::details::has_dereference_class< T, Enable >

Class defining whether the specified type can be dereferenced.

Template Parameters

T	the type to be tested for dereferenciation
Enable	triggers the conditional compilation

Usage:

static_assert(!has_dereference_class<int>::value, "error");
static_assert(has_dereference_class<int*>::value, "error");

Implementation details

The class is implemented by two definitions:

1. a general one, always equivalent to std::false_type
2. a special one, always equivalent to std::true_type, defined only if the type T can be dereferenced (that is, if *(T()) is valid)

The selection mechanism will always select the second form if available, since it is more specialized.

Definition at line 51 of file Dereference.h.

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The documentation for this struct was generated from the following file:

• Dereference.h